In return the water pushes the swimmer forwards, thus allowing him to go forward during swimming. (a) Given, the bust starts from rest. NCERT Solutions for Class 9th: Ch 8 Motion Science In Text Question Page No: 100 1. If the initial position of the farmer is at one corner of the field, the terminal position would be at the opposite corner (since the field is square).In this case, the total displacement of the farmer will be equal to the length of the diagonal line across the opposite corners of the square.Applying the Pythagoras theorem, the length of the diagonal can be obtained as follows: If the initial position of the farmer is at the mid-point between two adjacent corners of the square, the net displacement of the farmer would be equal to the side of the square, which is 10m. Here are the solutions of intext questions and exercises of CBSE Class 9 Science Chapter 8. NCERT Solutions for Class 9 Science Chapter 8 PDF is also updated as per syllabus updates. You must follow the exact representation in a velocity-time chart.You have to find speed acquired and distance traveled by bus in this question. Yes, an object moving a certain distance can have zero total displacement. Therefore, the net displacement will be equal to the diameter of the track, which is 200m.Therefore, the net distance covered by the athlete is 2200 meters and the total displacement of the athlete is 200m.Given, distance covered from point A to point B = 300 metersDistance covered from point A to point C = 300m + 100m = 400 metersTime taken to travel from point A to point B = 2 minutes and 30 seconds = 150 secondsTime taken to travel from point A to point C = 2 min 30 secs + 1 min = 210 secondsDisplacement from A to C = 300m – 100m = 200 metersAverage speed = total distance travelled/ total time takenAverage velocity = total displacement/ total time takenTherefore, the average speed while traveling from A to B = 300/150 msAverage speed while traveling from A to C = 400/210 msAverage velocity while traveling from A to B =300/150 msAverage velocity while traveling from A to C =200/210 msDistance traveled to reach the school = distance traveled to reach home = d (say)therefore, average speed while going to school = total distance travelled/ total time taken = d/tAverage speed while going home = total distance travelled/ total time taken = d/tNow, the average speed for the entire trip is given by total distance travelled/ total time takenTherefore, Abduls average speed for the entire trip is 24 kilometers per hour.Therefore, the total distance traveled by boat in 8 seconds = 0 + 1/2 (3)(8)Therefore, the motorboat travels a distance of 96 meters in a time frame of 8 seconds.The speed v/s time graphs for the two cars can be plotted as follows.The total displacement of each car can be obtained by calculating the area beneath the speed-time graph.Therefore, displacement of the first car = area of triangle AOBTherefore, the area of the triangle AOB is given by: (1/2)*(5s)*(14.44msNow, the displacement of the second car is given by the area of the triangle CODTherefore, area of triangle COD = (1/2)*(10s)*(0.83msTherefore, the first car is displaced by 36 meters whereas the second car is displaced by 4.15 meters.
NCERT Solutions for Class 8 Science Chapter 9 – 2 Mark Questions and Answers. The logical explanation provided in Motion Class 9 questions answers is helpful as it clears the basics of the crucial topic of Physics - Motion. A train starting from a railway station and moving with uniform acceleration attains a speed 40 km h1. Velocity can hold a negative value as well. NCERT Solutions for Class 9 science is the contribution by the faculty having vast teaching experience. MCQ Questions for Class 9 Science Chapter 8 Motion with Answers MCQs from Class 9 Science Chapter 8 – Motion are provided here to help students prepare for their upcoming Science exam. The most preferred questions and their answers also provide a better understanding of the whole chapter for you. In case you get stuck, NCERT Class 9 Science Chapter 8 Exercise Solution for Motion provides a comprehensive solution for the same.From this question, the understanding of graphs and representations is checked. The answer provided covers all significant points of distinction between the two.The ideas of uniform and non-uniform acceleration are checked here. You can easily download the best CBSE NCERT Solutions from the online portal of Vedantu. NCERT Solutions for Class 9 Science. What can you say about the motion of an object if its speed – ‘time graph is a straight line parallel to the time axis?4.